Atomic Spectra icon


In this lab you will observe the visible spectrum of Hydrogen and use it to measure the Rydberg constant. Then you will use the spectrum of two unknown sources to determine their atomic content.

Background

The quantum explanation for atomic structure was developed in the early 1900’s based largely on measurements of the wavelengths of light emitted by atoms in gas-discharge lamps.
These measurements, first made in the late 1800’s, provided evidence that the energy levels of atoms are quantized (i.e. have a discrete set of possible values). In particular, in 1885, Johann Balmer measured the visible spectrum of Hydrogen and found the wavelengths of light that were present were related according to

1λ=R(1221n2);forn>2.\frac{1}{\lambda} = R\left(\frac{1}{2^2}-\frac{1}{n^2}\right); \,\,\,\mathrm{for}\,\,n>2.
Equation 1

The ultraviolet and infrared portions of the Hydrogen spectrum were later measured (by Lyman, Paschen, Brackett and Pfund) and found to fit similar formulas but with integers other than 2 in the first term (and in the inequality). They all measured the same coefficient, RR, called the Rydberg constant.

The origin of this formula was eventually understood within the Bohr model of the atom, which posited that the light from Hydrogen consists of photons of energy E=hν=hc/λE = h\nu = hc/\lambda that are emitted by atoms transitioning between electronic states that have discrete energies of En=hcR/n2E_n = -hcR/n^2, where cc is the speed of light, hh is Planck's constant, RR is the Rydberg constant and nn is a positive integer (Fig. 1). Transitions from excited states to the n=2n = 2 state produce visible light (red to violet, left to right for the four lines shown) that you will observe in this lab. Transitions to the n=1n = 1 state produce ultraviolet light, and those to the n=3n = 3 state produce infrared light, neither of which can be seen by eye.

levels

Diagram of the energy levels for a Hydrogen atom.

Figure 1

This understanding allowed the Rydberg constant to be formulated in terms of purely fundamental constants like the mass, mm, and charge, ee, of the electron and the permittivity of free space, ϵ0\epsilon_0:

R=me4/8ϵ0h3c,R = me^4/8\epsilon_0h^3c\,,

whereas previously it had been only an empirically determined value. [1]

In this lab, you will measure the visible spectrum of Hydrogen as Balmer originally did and, from it, obtain a measurement of the Rydberg constant.

Note that the Rydberg constant applies only to Hydrogen. Other atoms have a similar 1/n21/n^2 structure to the equation that describes their spectra, but with a different coefficient. Each element’s spectrum is uniquely characteristic, so spectra are often used to identify the elemental composition of a sample (or a star! [2]).

After you completing your measurements of the Hydrogen spectra, you will measure the visible spectra of two unknown samples and use them to identify each sample's elemental composition.

Instruments

The apparatus used in this lab consists of

lamp

Figure 2

carousel

You can see a top-down view of the carousel at the very right of the "overview" live feed, but the view is complicated and obstructed by various 3D-printed parts that help position and motorize the apparatus. A mirror just to the right of center near the top of the "overview" feed reflects a sideview that clearly shows when a lamp is on, off and/or rotating into position.

Figure 3

grating

Figure 4

You have learned about interference in the context of collimated light passing through a double slit. In another lab in this course, you may have experimented with passing light through an array of three, four or five slits. When collimated light passes through multiple, equally spaced slits, the result is an intensity pattern with maxima and minima at the same positions as in the pattern created by two slits with the same spacing, but with maxima that are much more narrowly peaked, (i.e., the contrast is much improved).

The diffraction grating you will use was made from an etching of thin parallel lines on a piece of glass. Etched regions scatter light instead of transmitting it, so the non-etched regions between the etched lines act as slits. The etching process allows hundreds or thousands of lines per mm, so this type of diffraction grating has slits that are not only plentiful, but closely spaced as well.

Because of its very large number of slits, the diffraction grating creates very sharp maxima. Because of their close spacing, the slits impose a large "lever arm" on the pattern (i.e. a greater angular separation between maxima) making it possible to distinguish maxima of subtly different wavelengths. This can be seen from the equation for constructive interference. Light passing through slits separated by a distance dd will have intensity maxima at angles θm\theta_m for which

dsinθm=mλ,d \sin \theta_m = m\lambda\,,

where mm is any positive integer. The smaller dd is, the larger θm\theta_m will be for the same λ\lambda.

The m=0m = 0 case is the central maximum. By measuring θm\theta_m for m=1m = 1 maxima for each of the different wavelengths, you can precisely determine those wavelengths. [3]

Note that this equation applies only if the collimated light is "normally incident" on the grating. You may have to adjust the grating to make this be the case.[^4]

Question 1

What is the spacing dd for the diffraction grating? (Hint: See Figure 4.)

spectroscope

A manual for the spectropscope is available in PDF format on the web-portal for this experiment.

Figure 5

spectroscopeDiagram

The parts of the spectroscope are more easily distinguished in a diagram.
(Note that this diagram's vantage point is rotated slightly (~45° CCW) from that in the photo: the arms that are angled toward the viewer in the photo are angled away from the viewer in the diagram.)

Figure 6

Two cylinders define the light path: the collimator (C); and the telescope (E). The collimator has an opening at its far end that only admits light through a vertical slit (B). The width of the slit is narrow but adjustable. It shapes the light beam into a vertical line. Letting the light spread vertically doesn’t degrade the resolution in θ\theta because θ\theta is an angle in the horizontal plane. Because a line allows more light to hit the detector, it is much easier to determine the location of a line than a point. The use of vertical slits in spectral measurements is so common that the observed maxima are called spectral lines.

The telescope swings to different angles around the grating (A) and images the light that comes through the grating onto a detector. The lens at the far end of the telescope is called an "eyepiece". If this were an in person lab, you would look through the eyepiece and your eye would be the detector. To allow you to view the lines remotely, we have put a webcam behind the eyepiece and made what it sees available to you by clickling on the "eyepiece" button.

The angular position of the telescope is read off of scales (I,J) situated on either side of the spectrometer. The scales measure degrees down to one arc minute with Vernier markings.

Using a Vernier scale takes a bit of explanation and some practice. There are some good extended descriptions online (e.g. in Wikipedia), so here we’ll introduce it with a few examples specific to the scales you will be using. The scales on the spectroscope consist of two sets of uniformly spaced lines that are arranged so that they slide past each other. The lower set's lines mark each half degree, while the upper one's (which are very slightly more closely spaced) have markings corresponding to 0-30 arc minutes. The two scales are used together.

vernierLeft

Figure 7

Cartoons of two different measurements are shown in Figure 7 to illustrate the procedure. First you look where the zero mark on the inner scale is located. In the left hand cartoon that is to the right of 210210^\circ; in the right hand cartoon it is to the right of 229.5229.5^\circ. Then you look where the lines on the inner and outer scales align most closely. In the left hand cartoon that happens for the 1515^\prime mark; on the right side it happens at the 1616^\prime mark. These measure the number of arc minutes to add to the values obtained from the first step. So, the measurement on the left side is 210+15=210+(15/60)=210.250210^\circ + 15^\prime = 210^\circ + (15/60)^\circ = 210.250^\circ, and the measurement on the right is 229.5+16=229.5+(16/60)=229.767229.5^\circ + 16^\prime = 229.5^\circ + (16/60)^\circ = 229.767^\circ.

Question 2

What is the angular position indicated by the vernier scales in the photo in the middle of Figure 7?

The precision of these θ\theta readings is limited by the one arc minute granularity of the Vernier scale, but it is possible to make mistakes in reading or calculating the values. Here are a few things you can do to reduce the chance of such mistakes and their impact:

  1. Have someone else (e.g. your lab partner) make the same reading (without telling them what you got) and compare.
  2. Recall that the position of the telescope can be read off of scales situated on either side of the spectrometer. The angles recorded by the two scales should differ by exactly 180180^\circ. Read and record both. If, after correcting for the 180180^\circ difference, you find that their values differ by more than the 0.0050.005^\circ precision of the scales, something is wrong - if not with your readings, then with the spectrometer itself (*e.g., warping of the scales). This approach of making multiple, independent measurements of the same quantity is always a good idea and helps validate your results.
  3. Record your raw readings in degrees and arc minutes, and then calculate the corresponding decimal degree values. This will help you disentangle any calculation errors that may occur. While the calculations in this case are not complicated, and the consequences of a mistake are small, this sort of fastidious data recording is a good habit to develop for professional laboratory work, when both the chances and consequences of mistakes increase.

Finally, be aware that the Verniers read angular position but the location of 00^\circ is arbitrary.

In order to determine the wavelength using dsinθ=λd\sin\theta = \lambda, where θ\theta is the angle between maxima, you need to measure two angles and subtract, just like measuring a length requires two position measurements. You could do this by measuring the angular position of the central maximum, which we can call θ0\theta_0 , and the angular position of the m=+1m = +1 maximum, which we can call θ+1\theta_{+1}. Then λ=dsin(θ+1θ0)\lambda = d\sin(\theta_{+1}-\theta_0). Similarly, you could measure the angular position of the m=+2m = +2 maximum and use 2λ=dsin(θ+2θ0)2\lambda = d \sin (\theta_{+2}-\theta_0) or λ=dsin(θ+2θ+1)\lambda = d \sin (\theta_{+2}-\theta_{+1}). Finally, note that the direction in which the angles increase or decrease on the scale is arbitrary, so you should use the absolute value of the differences.

Approach

Using the instruments above, you will determine the wavelengths of light emitted by three different gasses.

The web-portal for this experiment enables you to manipulate the spectroscope, see the lines and read the verniers just as you would in person.

Overview

Note the timer at the top of the portal (in red). When it runs out, the lab equipment will reset to its initial configuration.

Figure 8

Exercise 1

When you first open the portal the video feed will be dark. A row of blue buttons immediately above the video feed lets you select among four cameras. OVERVIEW gives a top-down view of the apparatus, centered on the diffraction grating; EYEPIECE shows the view through the eyepiece; VERNIER1 and VERNIER2 each look at one of the two Vernier scales.

Bluebuttons

The ambient light lets you observe the setup and better see the machinery respond to your clicks.

Ambient light reflecting off of the diffraction grating lights up the circular field of view of the eyepiece. It can't be confused for the vertical lines of light from the lamp, but it can make it hard for you to see very dim lines, so you should consider turning off the ambient light when taking your data.

Question 3

What is the angular position of the telescope?

Schematic

Above the camera control buttons is a schematic of the spectrometer. Green, pink and yellow arrows in the schematic enable you to move the telescope, grating and lamp, respectively. Correspondingly colored radio buttons allow you to change the amount moved per click.

It can be difficult to see/click on the arrows and radio buttons while also viewing the live feed because of a need to scroll the page up and down. A button on the left, labeled "Moveable Schematic", opens a window with just the arrow and radio buttons that you can position wheverever you want on your screen.

Question 4

What is the angular position of the telescope now?

Question 5

Describe what you did to get it there.

The collimator and the telescope should be co-linear.

Question 6

What color is the light from the H2 lamp?

You should see the illuminated slit near the center of the field of view.

Notice that two new controls appear when you select the Eyepiece view.

Eyepiece

Figure 9

On the left is a button that lets you position a set of crosshairs over the live feed.

On the right is a photo of the slit with green arrows that let you change its width among three positions when you use the "coarse" setting.

Question 7

How many pixels wide is the slit in each setting? (Hint: use the crosshairs.)

Question 8

What are the original values of the various camera settings?

Keep in mind that increasing the slit width, adjusting the camera settings and turning the background black may be helpful when viewing very dim lines.

Measurement

Now that you have familiarized yourself with the spectroscope and have it aligned on the central maximum, you are ready to measure the Hydrogen spectrum!

Exercise 2

Data Collection

Question 9

In which direction did you move the telescope?

Question 10

Which color line appears closest, and which appears furthest, from the central maximum?

Note that the violet line is the dimmest of the four and can be difficult to see. You can increase the slit width to make the lines easier to see, but you will want to balance the need for visibility with the desire for narrow lines that can be measured more precisely.

Question 11

How do the intensities of the lines in this direction compare with the ones you saw in the other direction?

Diffraction gratings are often designed to concentrate most of the diffracted energy in a particular maximum for a given wavelength. This is done by shaping, or "blazing" the grooves to have a triangular profile. The grating in this apparatus is blazed for an m=+1m=+1 maximum of a visible wavelength, which is why the lines are much brighter on one side of the central maximum compared to the other.

Question 12

What is the horizontal position of the central maximum in the live feed? (Hint: use the crosshairs.)

Question 13

What is the angular position of the telescope? Remember to record the readings from both VERNIER1 and VERNIER2.

Question 14

What is the coversion between pixels and degrees? Show your work.

Question 15

What are the colors and angular positions of each of the four m=1m=1 lines? Remember to record the readings from both VERNIER1 and VERNIER2.

Question 16

Can you see any of the m=2m=2 lines? Note the angular position and color of any you can see. Remember to record the readings from both VERNIER1 and VERNIER2.

\Rightarrow Make sure your data appears in a well-formatted table in your notes. \Leftarrow

Question 17

What are the colors and angular positions of the m=1m=-1 lines that you can see? Remember to record the readings from both VERNIER1 and VERNIER2 and to properly account for any Δ\Delta in the eyepiece camera view.

You may see a background of colors in addition to the main bright lines. This background is typically due to the ultraviolet light emitted by the hydrogen lamp exciting other atoms to emit. In fact, that is how fluorescent lights work. Ultraviolet emission produced by running a current through the gas in a long tube excites atoms in the white fluorescent material that coats the inside of the tube. That material then emits a large number of different wavelengths that we perceive as white light.

Exercise 3

Data Analysis

In a spreadsheet, calculate the θm\theta_m values of the various lines from the angular positions you measured. Recall that θm\theta_m = θcentralmaximumθline\theta_\mathrm{central\, maximum} - \theta_\mathrm{line} .

Question 18

Which angular positions did you subtract for each value of θm\theta_m?

\Rightarrow Include this well-formatted table in your notes. \Leftarrow

Using the θm\theta_m values you calculated and the condition for constructive interference (given in the diffraction grating section above), calculate the wavelength of each of the Balmer lines.

Question 19

What is the wavelength you measured for the n=3n=3 Balmer line?

Question 20

What are the wavelengths you measured for the n=4,5,6n={4,5,6} Balmer lines?

Look at Equation 1 :

1λ=R(1221n2);forn>2.\frac{1}{\lambda} = R\left(\frac{1}{2^2}-\frac{1}{n^2}\right); \,\,\,\mathrm{for}\,\,n>2.

Question 21

To make a plot of your data that will let you fit a straight line whose slope will be the Rybderg constant, RR, what should you plot on the yy-axis? What should you plot on the xx-axis?

\Rightarrow Include this well-formatted plot in your notes. \Leftarrow

Question 22

What is the value of the Rydberg constant indicated by your data?

The currently accepted value of the Rydberg constant is R=0.0109678 nm1R=0.0109678~\mathrm{nm}^{-1}. [5]

Question 23

How large a fraction of the accepted value is the discrepancy between your measurement of the Rydberg constant and the accepted value?

Calculate this proportionate discrepancy by taking the difference and dividing it by the accepted value:

RmeasuredRacceptedRaccepted.\frac{|R_\mathrm{measured}-R_\mathrm{accepted}|}{R_\mathrm{accepted}}\,.

Give your answer as a percentage.

Exercise 4

Identify the unknowns

There are two other spectral lamps in the carousel, labeled "A" and "B". They are each filled with one of the Noble gases. At the bottom of the web-portal are two copies of the following image naming the five noble gases:

Noble Gases

Click on one of the boxes naming an element to see its detailed spectrum and on the other to see the wavelengths and relative intensities of its major peaks.

Question 24

Which lamp did you choose?

Question 25

In order of brightness, starting with the brightest, what are the θ1\theta_1 values of those four lines? What are their wavelengths. For full credit, show your work.

Question 26

Which element is in this lamp? Explain your reasoning.

Question 27

In order of brightness, starting with the brightest, what are the θ1\theta_1 values of those four lines? What are their wavelengths. For full credit, show your work.

Question 28

Which element is in this lamp? Explain your reasoning.

[1]: Interestingly, the measured value of RR did not match the prediction of the simplest Bohr model which uses m=mem = m_e because the electron and proton together lead to an effective “reduced mass”, mm, that is very slightly below the electron mass. Furthermore, the spectrum of hydrogen was found to contain a set of wavelengths with a slightly different RR value. These come from deuterium, which is hydrogen with a neutron in the nucleus, the mass of which further alters mm). Both effects are smaller than 0.1% and only revealed by exquisitely precise measurements.

[2]: It is amusing to note how often dialogue in Star Trek episodes involves the captain asking for a “multi-spectral analysis” of some anomaly. Analyzing the spectrum of astrophysical objects is common, in fact so common that it would be done automatically, without the captain’s specific request! But it does provide tech-y sounding, and in this case not incorrect, dialogue.

[3]: To validate your results, it is good practice to measure θm\theta_m values for other values of mm, but be aware that the grating is optimized for m=+1m=+1, so the other maxima can be hard to see.

[4]: If the collimated light hits the diffraction grating at some other angle θi0\theta_i \neq 0, the equation becomes d(sinθisinθ±m)=±mλd (\sin \theta_i \mp \sin \theta_{\pm m}) = \pm m\lambda, where the angles are measured from the grating's normal. If θi0\theta_i \gg 0^\circ and you neglect the θi\theta_i-term, you will have a systematic error in your wavelength measurements. Fortunately, it is easy to either (i) determine θi\theta_i directly using the overview camera, which is positioned directly above the grating's axis of rotation, or (ii) cancel out its effect by measuring θ\theta for two different values of m0m \neq 0 for the same wavelength and substracting the corresponding equations to cancel out the θi\theta_i-term.

[5]: This value takes into account the effective reduced mass of the electron in the Hydrogen atom. See Wikipedia for elaboration.